Consider myo as a 2-dimensional array.
The maximum value is max(max(myo)); => k
max(myo) => will give an array like [0 5 6 0]
[code:1:f21d2c370e]k = (max(max(myo))); answer = find(max(myo) == k,1)[/code:1:f21d2c370e]
[b:f21d2c370e]myo [/b:f21d2c370e]=
[0 5 6 0
1 2 5 4]
[b:f21d2c370e]max(myo)[/b:f21d2c370e] = [b:f21d2c370e]k[/b:f21d2c370e]
6
[b:f21d2c370e]answer [/b:f21d2c370e]will be 3 ( 6 has position 3 in the array ).
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